evaluation-implementation-of-postfix-notation-Data-Structure
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#evaluation-implementation-of-postfix-notation-Data-Structure
Postfix notation, also known as Reverse Polish Notation (RPN), is a mathematical notation where operators follow their operands. Unlike infix notation (e.g., 4 + 5), postfix notation eliminates the need for parentheses to define order of operations. This makes it especially useful for computer systems and programming languages that work with stacks to evaluate expressions efficiently.
In this article, we explore how to evaluate and implement postfix notation in C programming with a focus on data structures. We’ll also discuss its practical applications and provide code examples to help you understand its implementation.
In postfix notation:
For example, the postfix expression 4 5 6 * +
translates to:
30
34
This sequence eliminates the ambiguity of operator precedence found in infix notation.
Postfix expressions are evaluated using a stack:
Here’s how you can implement postfix evaluation in C using a stack:
#include <stdio.h>
#include <conio.h>
#include <ctype.h>
#define MAX 50
float stack[MAX];
int top = -1;
// Function to push a value onto the stack
void push(float val) {
if (top == MAX - 1) {
printf("\nStack Overflow");
return;
}
stack[++top] = val;
}
// Function to pop a value from the stack
float pop() {
if (top == -1) {
printf("\nStack Underflow");
return -0.0;
}
return stack[top--];
}
void main() {
char post[50];
int i = 0;
float A, B, C;
clrscr(); // Clears the screen (specific to Turbo C; replace for other compilers)
printf("\nEnter any expression in postfix notation (in Numeric Form): ");
scanf("%s", post);
while (post[i] != '\0') {
if (isdigit(post[i])) { // If the character is a digit
push(post[i] - '0'); // Convert character to number
} else if (post[i] != ' ') { // If it's an operator
A = pop();
B = pop();
switch (post[i]) {
case '+': C = B + A; break;
case '-': C = B - A; break;
case '*': C = B * A; break;
case '/': C = B / A; break;
default: printf("\nInvalid operator"); return;
}
push(C); // Push the result back onto the stack
}
i++;
}
printf("\nAnswer of Postfix Expression = %f", pop());
}
23*5+
Let’s evaluate the postfix expression 23*5+
step by step:
2
and 3
onto the stack.*
: Pop 3
and 2
, calculate 2 * 3 = 6
, and push 6
back.5
onto the stack.+
: Pop 5
and 6
, calculate 6 + 5 = 11
.11
.In this article, we discussed the evaluation and implementation of postfix notation in data structures using C. By leveraging stacks, postfix expressions can be evaluated efficiently and without ambiguity. The provided code demonstrates how to handle operands and operators dynamically, ensuring a clear and effective solution.
Whether you're working on compilers, calculators, or learning advanced data structures, mastering postfix notation is a valuable skill. Try implementing the code with different expressions to deepen your understanding!